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IGCSE Maths6 min

IGCSE Standard Form: Powers of Ten, Calculations and Calculator E Notation

Learn IGCSE standard form with worked examples of large and small numbers, multiplication, division, addition and scientific calculator E notation.

By Math School Editorial Team

Audience and search intent: Cambridge IGCSE Mathematics 0580 Core and Extended learners and parents searching for a clear guide to standard form (scientific notation), including interpreting calculator displays.

Editorial image brief: Create an original split-panel vector graphic: left shows 3,750,000 changing to 3.75 × 10⁶; right shows 0.000092 changing to 9.2 × 10⁻⁵; a small calculator display reads 6.4E−3. Include labelled place-value arrows and large, legible typography. Alt text: “Large and small numbers converted to IGCSE standard form, with an example of calculator E notation.” Rights: Produce from scratch using owned shapes and typography or a commercially licensed designer; do not reproduce Cambridge diagrams, calculator-brand logos, textbook figures or stock images without appropriate rights. No image has been generated yet.

Why does IGCSE mathematics use standard form?

A distance can be millions of metres, while a measurement in science may be a tiny fraction of a metre. Long strings of zeroes are awkward to read, compare and calculate with. Standard form, also called scientific notation, expresses the size of a number through a power of ten.

In Cambridge IGCSE Mathematics (0580), standard form is part of the Number content for both Core and Extended candidates (sections C1.8 and E1.8 of the 2025–2027 syllabus). The syllabus requires students to use, convert and calculate with numbers in standard form. For Core candidates, calculations with standard form are expected on calculator Paper 3; Extended candidates may need to calculate without a calculator on Paper 2. Always use the syllabus for your examination year.

1. Learn the rule before moving any decimal point

A number in standard form has the structure

A×10nA \times 10^n

where 1≤A<101 \le A < 10 and nn is an integer. The first factor must be at least 1 but less than 10. The power tells us how many places the decimal point shifts when we write the ordinary number.

For example, 37.5×10537.5 \times 10^5 has the correct value but is not written in standard form because 37.5 is too large for the first factor. The standard-form version is 3.75×1063.75 \times 10^6.

2. Large numbers: a positive exponent

Write 3,750,000 in standard form. Put the decimal after the first non-zero digit to obtain 3.75. To return from 3.75 to 3,750,000, the decimal moves six places to the right. Therefore:

3 750 000=3.75×1063\,750\,000=3.75\times10^6

A positive power indicates a factor of ten greater than or equal to one; for example, 10610^6 is one million. It does not mean that the original number must be positive: −3.75×106-3.75\times10^6 is a valid way to represent a negative large number, with the sign written outside the positive coefficient.

3. Small numbers: a negative exponent

Write 0.000092 in standard form. The first significant digits are 9 and 2, giving 9.2. To get back to 0.000092, shift the decimal five places to the left:

0.000092=9.2×10−50.000092=9.2\times10^{-5}

Remember that 10−5=1/100 00010^{-5}=1/100\,000. The negative exponent describes a reciprocal power of ten; it does not make the number itself negative.

4. Multiply: combine the coefficients and powers separately

Calculate (6×107)(2.5×10−3)(6\times10^7)(2.5\times10^{-3}).

Multiply the coefficients: 6×2.5=156\times2.5=15. Add the powers because 107×10−3=10410^7\times10^{-3}=10^4. The intermediate result is 15×10415\times10^4, but 15 is not between 1 and 10. Normalise it:

15×104=1.5×10515\times10^4=1.5\times10^5

A useful check: a number around sixty million multiplied by a number around 0.0025 should be around 150,000, not 150 million.

5. Divide: subtract the exponents

Calculate (8.4×10−5)/(2.1×102)(8.4\times10^{-5})/(2.1\times10^2).

Divide the coefficients: 8.4/2.1=48.4/2.1=4. Subtract the exponents: −5−2=−7-5-2=-7. So:

8.4×10−52.1×102=4×10−7\frac{8.4\times10^{-5}}{2.1\times10^2}=4\times10^{-7}

This is a particularly good place to practise the difference between −5−2=−7-5-2=-7 and the incorrect −5+2=−3-5+2=-3.

6. Add or subtract: first make the powers match

Unlike multiplication, addition does not allow you to add exponents. To calculate 3.2×105+4.7×1043.2\times10^5+4.7\times10^4, rewrite the second term as 0.47×1050.47\times10^5:

(3.2+0.47)×105=3.67×105(3.2+0.47)\times10^5=3.67\times10^5

The same principle works for subtraction. Choose a shared power of ten, combine the coefficients, then normalise if needed.

7. What does E mean on a calculator?

A calculator might show 6.4E−3, 6.4 EXP −3, or 6.4 × 10⁻³, depending on its model and display mode. In this context, E is shorthand for “times ten to the power of”. Thus:

6.4E−3=6.4×10−3=0.00646.4E{-3}=6.4\times10^{-3}=0.0064

It is not the algebraic variable ee, and it is not the mathematical constant e≈2.718e\approx2.718. Calculator layouts differ, so learners should practise reading the actual model permitted in their examination. Cambridge's 2025–2027 syllabus states that Paper 1 (Core) and Paper 2 (Extended) are non-calculator, while Papers 3 and 4 require a scientific calculator.

8. Five mistakes to check before handing in your answer

  1. The coefficient must be at least 1 and less than 10 in magnitude; if a negative number is represented, put the minus sign in front.

  2. A negative power of ten makes the magnitude small, not automatically negative.

  3. When multiplying powers of ten, add the exponents; when dividing, subtract.

  4. When adding or subtracting numbers in standard form, align the exponents first.

  5. Check the order of magnitude by estimating before accepting a calculator answer.

Original practice questions

Try these without looking at the solutions.

  1. Write 0.00000608 in standard form.

  2. Write 5.6×1045.6\times10^4 as an ordinary number.

  3. Evaluate (3×106)(4×10−2)(3\times10^6)(4\times10^{-2}) in standard form.

  4. Evaluate (9×10−4)/(3×102)(9\times10^{-4})/(3\times10^2) in standard form.

  5. Calculate 7.2×105−4.5×1047.2\times10^5-4.5\times10^4 in standard form.

Answers and reasoning

  1. 6.08×10−66.08\times10^{-6}: the decimal must move six places right to reach 6.08.

  2. 56,000: multiply 5.6 by 10,000.

  3. 1.2×1051.2\times10^5: 3×4=123\times4=12 and 6+(−2)=46+(-2)=4; then normalise 12×10412\times10^4.

  4. 3×10−63\times10^{-6}: 9/3=39/3=3 and −4−2=−6-4-2=-6.

  5. 6.75×1056.75\times10^5: write 4.5×1044.5\times10^4 as 0.45×1050.45\times10^5 and subtract 7.2−0.45=6.757.2-0.45=6.75.

A 15-minute revision routine

Spend four minutes converting two large and two small numbers; four minutes on one multiplication and one division; four minutes on addition or subtraction with different powers; and three minutes checking calculator displays and explaining why the coefficient must be between 1 and 10. Ask your child to explain why an exponent is positive or negative rather than memorising a decimal-moving rule.

Official sources and fact-check notes — 2 November 2026